009C Sample Midterm 2, Problem 2 Detailed Solution

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Determine convergence or divergence:

Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \sum _{n=1}^{\infty }{\frac {3^{n}}{n}}}


Background Information:  
Direct Comparison Test
        Let    and    be positive sequences where  
        for all    for some  
        1. If    converges, then    converges.
        2. If    diverges, then    diverges.


Solution:

Step 1:  
First, we note that
        Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {3^{n}}{n}}>0}
for all  
This means that we can use a comparison test on this series.
Let  Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle a_{n}={\frac {3^{n}}{n}}.}
Step 2:  
Let  
We want to compare the series in this problem with
        Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle \sum _{n=1}^{\infty }{\frac {1}{n}}.}
This is the harmonic series (or  -series with  Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle p=1.}  )
Hence,    diverges.
Step 3:  
Also, we have  Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle b_{n}<a_{n}}   since
        Failed to parse (Conversion error. Server ("https://wikimedia.org/api/rest_") reported: "Cannot get mml. Server problem."): {\displaystyle {\frac {1}{n}}<{\frac {3^{n}}{n}}}
for all  
Therefore, the series    diverges
by the Direct Comparison Test.


Final Answer:  
        diverges (by the Direct Comparison Test)

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